# Line slope calculator 7x+6y=62

**Straight line given by points A[2; 8] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -1.1667x+10.3333

**Canonical form of the line equation:**7x+6y-62 = 0

**Parametric form of the line equation:**

x = 6t+2

y = -7t+8 ; t ∈ R

**Slope:**m = -1.1667

**Slope angle of line: φ =**-49°23'55″ = -0.8622 rad

**X intercept:**x

_{0}= 8.8571

**Y intercept:**y

_{0}= q = 10.3333

**Distance line from the origin:**d

_{0}= 6.7248

**The length of the segment AB: |AB| =**9.2195

**Vector: AB =**(6; -7)

**Normal vector: n =**(7; 6)

**Midpoint of the segment AB: M =**[5; 4.5]

**Perpendicular Bisector equation:**6x-7y+1.5 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 68°50'19″ = 1.2015 rad**